TIMEOUT

The TRS could not be proven terminating. The proof attempt took 60029 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (67ms).
 | – Problem 2 was processed with processor SubtermCriterion (2ms).
 | – Problem 3 was processed with processor SubtermCriterion (0ms).
 | – Problem 4 was processed with processor SubtermCriterion (1ms).
 | – Problem 5 was processed with processor SubtermCriterion (0ms).
 | – Problem 6 was processed with processor SubtermCriterion (1ms).
 | – Problem 7 remains open; application of the following processors failed [SubtermCriterion (0ms), DependencyGraph (1ms), PolynomialLinearRange4iUR (1793ms), DependencyGraph (1ms), PolynomialLinearRange8NegiUR (29996ms), DependencyGraph (timeout), ReductionPairSAT (1218ms), DependencyGraph (2ms), SizeChangePrinciple (950ms), ForwardNarrowing (0ms), BackwardInstantiation (1ms), ForwardInstantiation (1ms), Propagation (1ms)].

The following open problems remain:



Open Dependency Pair Problem 7

Dependency Pairs

f#(s(x))f#(-(max(*(s(x), s(x)), +(s(x), s(s(s(0))))), max(s(*(s(x), s(x))), +(s(x), s(s(s(s(0))))))))

Rewrite Rules

min(0, y)0min(x, 0)0
min(s(x), s(y))s(min(x, y))max(0, y)y
max(x, 0)xmax(s(x), s(y))s(max(x, y))
+(0, y)y+(s(x), y)s(+(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
*(x, 0)0*(x, s(y))+(x, *(x, y))
f(s(x))f(-(max(*(s(x), s(x)), +(s(x), s(s(s(0))))), max(s(*(s(x), s(x))), +(s(x), s(s(s(s(0))))))))

Original Signature

Termination of terms over the following signature is verified: f, min, max, 0, s, *, +, -


Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

f#(s(x))-#(max(*(s(x), s(x)), +(s(x), s(s(s(0))))), max(s(*(s(x), s(x))), +(s(x), s(s(s(s(0)))))))*#(x, s(y))*#(x, y)
f#(s(x))+#(s(x), s(s(s(s(0)))))f#(s(x))max#(s(*(s(x), s(x))), +(s(x), s(s(s(s(0))))))
max#(s(x), s(y))max#(x, y)f#(s(x))+#(s(x), s(s(s(0))))
+#(s(x), y)+#(x, y)-#(s(x), s(y))-#(x, y)
*#(x, s(y))+#(x, *(x, y))f#(s(x))f#(-(max(*(s(x), s(x)), +(s(x), s(s(s(0))))), max(s(*(s(x), s(x))), +(s(x), s(s(s(s(0))))))))
min#(s(x), s(y))min#(x, y)f#(s(x))*#(s(x), s(x))
f#(s(x))max#(*(s(x), s(x)), +(s(x), s(s(s(0)))))

Rewrite Rules

min(0, y)0min(x, 0)0
min(s(x), s(y))s(min(x, y))max(0, y)y
max(x, 0)xmax(s(x), s(y))s(max(x, y))
+(0, y)y+(s(x), y)s(+(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
*(x, 0)0*(x, s(y))+(x, *(x, y))
f(s(x))f(-(max(*(s(x), s(x)), +(s(x), s(s(s(0))))), max(s(*(s(x), s(x))), +(s(x), s(s(s(s(0))))))))

Original Signature

Termination of terms over the following signature is verified: min, f, 0, max, s, *, +, -

Strategy


The following SCCs where found

f#(s(x)) → f#(-(max(*(s(x), s(x)), +(s(x), s(s(s(0))))), max(s(*(s(x), s(x))), +(s(x), s(s(s(s(0))))))))

min#(s(x), s(y)) → min#(x, y)

*#(x, s(y)) → *#(x, y)

max#(s(x), s(y)) → max#(x, y)

+#(s(x), y) → +#(x, y)

-#(s(x), s(y)) → -#(x, y)

Problem 2: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

*#(x, s(y))*#(x, y)

Rewrite Rules

min(0, y)0min(x, 0)0
min(s(x), s(y))s(min(x, y))max(0, y)y
max(x, 0)xmax(s(x), s(y))s(max(x, y))
+(0, y)y+(s(x), y)s(+(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
*(x, 0)0*(x, s(y))+(x, *(x, y))
f(s(x))f(-(max(*(s(x), s(x)), +(s(x), s(s(s(0))))), max(s(*(s(x), s(x))), +(s(x), s(s(s(s(0))))))))

Original Signature

Termination of terms over the following signature is verified: min, f, 0, max, s, *, +, -

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

*#(x, s(y))*#(x, y)

Problem 3: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

+#(s(x), y)+#(x, y)

Rewrite Rules

min(0, y)0min(x, 0)0
min(s(x), s(y))s(min(x, y))max(0, y)y
max(x, 0)xmax(s(x), s(y))s(max(x, y))
+(0, y)y+(s(x), y)s(+(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
*(x, 0)0*(x, s(y))+(x, *(x, y))
f(s(x))f(-(max(*(s(x), s(x)), +(s(x), s(s(s(0))))), max(s(*(s(x), s(x))), +(s(x), s(s(s(s(0))))))))

Original Signature

Termination of terms over the following signature is verified: min, f, 0, max, s, *, +, -

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

+#(s(x), y)+#(x, y)

Problem 4: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

-#(s(x), s(y))-#(x, y)

Rewrite Rules

min(0, y)0min(x, 0)0
min(s(x), s(y))s(min(x, y))max(0, y)y
max(x, 0)xmax(s(x), s(y))s(max(x, y))
+(0, y)y+(s(x), y)s(+(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
*(x, 0)0*(x, s(y))+(x, *(x, y))
f(s(x))f(-(max(*(s(x), s(x)), +(s(x), s(s(s(0))))), max(s(*(s(x), s(x))), +(s(x), s(s(s(s(0))))))))

Original Signature

Termination of terms over the following signature is verified: min, f, 0, max, s, *, +, -

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

-#(s(x), s(y))-#(x, y)

Problem 5: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

max#(s(x), s(y))max#(x, y)

Rewrite Rules

min(0, y)0min(x, 0)0
min(s(x), s(y))s(min(x, y))max(0, y)y
max(x, 0)xmax(s(x), s(y))s(max(x, y))
+(0, y)y+(s(x), y)s(+(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
*(x, 0)0*(x, s(y))+(x, *(x, y))
f(s(x))f(-(max(*(s(x), s(x)), +(s(x), s(s(s(0))))), max(s(*(s(x), s(x))), +(s(x), s(s(s(s(0))))))))

Original Signature

Termination of terms over the following signature is verified: min, f, 0, max, s, *, +, -

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

max#(s(x), s(y))max#(x, y)

Problem 6: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

min#(s(x), s(y))min#(x, y)

Rewrite Rules

min(0, y)0min(x, 0)0
min(s(x), s(y))s(min(x, y))max(0, y)y
max(x, 0)xmax(s(x), s(y))s(max(x, y))
+(0, y)y+(s(x), y)s(+(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
*(x, 0)0*(x, s(y))+(x, *(x, y))
f(s(x))f(-(max(*(s(x), s(x)), +(s(x), s(s(s(0))))), max(s(*(s(x), s(x))), +(s(x), s(s(s(s(0))))))))

Original Signature

Termination of terms over the following signature is verified: min, f, 0, max, s, *, +, -

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

min#(s(x), s(y))min#(x, y)