TIMEOUT

The TRS could not be proven terminating. The proof attempt took 60015 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (40ms).
 | – Problem 2 was processed with processor ForwardNarrowing (1ms).
 |    | – Problem 5 remains open; application of the following processors failed [ForwardNarrowing (1ms), BackwardInstantiation (1ms), ForwardInstantiation (1ms), Propagation (3ms), ForwardNarrowing (0ms), BackwardInstantiation (1ms), ForwardInstantiation (1ms), Propagation (2ms)].
 | – Problem 3 was processed with processor PolynomialLinearRange4iUR (319ms).
 |    | – Problem 4 was processed with processor PolynomialLinearRange4iUR (209ms).

The following open problems remain:



Open Dependency Pair Problem 2

Dependency Pairs

f#(c(x, y, z)) → f#(b(y, z))

Rewrite Rules

c(c(z, y, a), a, a) → b(z, y)f(c(x, y, z)) → c(z, f(b(y, z)), a)
b(z, b(c(a, y, a), f(f(x)))) → c(c(y, a, z), z, x)

Original Signature

Termination of terms over the following signature is verified: f, b, c, a


Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

f#(c(x, y, z)) → c#(z, f(b(y, z)), a)c#(c(z, y, a), a, a) → b#(z, y)
b#(z, b(c(a, y, a), f(f(x)))) → c#(y, a, z)b#(z, b(c(a, y, a), f(f(x)))) → c#(c(y, a, z), z, x)
f#(c(x, y, z)) → f#(b(y, z))f#(c(x, y, z)) → b#(y, z)

Rewrite Rules

c(c(z, y, a), a, a) → b(z, y)f(c(x, y, z)) → c(z, f(b(y, z)), a)
b(z, b(c(a, y, a), f(f(x)))) → c(c(y, a, z), z, x)

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy


The following SCCs where found

f#(c(x, y, z)) → f#(b(y, z))

b#(z, b(c(a, y, a), f(f(x)))) → c#(y, a, z)c#(c(z, y, a), a, a) → b#(z, y)
b#(z, b(c(a, y, a), f(f(x)))) → c#(c(y, a, z), z, x)

Problem 2: ForwardNarrowing



Dependency Pair Problem

Dependency Pairs

f#(c(x, y, z)) → f#(b(y, z))

Rewrite Rules

c(c(z, y, a), a, a) → b(z, y)f(c(x, y, z)) → c(z, f(b(y, z)), a)
b(z, b(c(a, y, a), f(f(x)))) → c(c(y, a, z), z, x)

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy


The right-hand side of the rule f#(c(x, y, z)) → f#(b(y, z)) is narrowed to the following relevant and irrelevant terms (a narrowing is irrelevant if by dropping it the correctness (and completeness) of the processor is not influenced).
Relevant TermsIrrelevant Terms
f#(c(c(_x22, a, _x21), _x21, _x23)) 
Thus, the rule f#(c(x, y, z)) → f#(b(y, z)) is replaced by the following rules:
f#(c(x, _x21, b(c(a, _x22, a), f(f(_x23))))) → f#(c(c(_x22, a, _x21), _x21, _x23))

Problem 3: PolynomialLinearRange4iUR



Dependency Pair Problem

Dependency Pairs

b#(z, b(c(a, y, a), f(f(x)))) → c#(y, a, z)c#(c(z, y, a), a, a) → b#(z, y)
b#(z, b(c(a, y, a), f(f(x)))) → c#(c(y, a, z), z, x)

Rewrite Rules

c(c(z, y, a), a, a) → b(z, y)f(c(x, y, z)) → c(z, f(b(y, z)), a)
b(z, b(c(a, y, a), f(f(x)))) → c(c(y, a, z), z, x)

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy


Polynomial Interpretation

Improved Usable rules

b(z, b(c(a, y, a), f(f(x)))) → c(c(y, a, z), z, x)c(c(z, y, a), a, a) → b(z, y)

The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:

b#(z, b(c(a, y, a), f(f(x)))) → c#(y, a, z)

Problem 4: PolynomialLinearRange4iUR



Dependency Pair Problem

Dependency Pairs

c#(c(z, y, a), a, a) → b#(z, y)b#(z, b(c(a, y, a), f(f(x)))) → c#(c(y, a, z), z, x)

Rewrite Rules

c(c(z, y, a), a, a) → b(z, y)f(c(x, y, z)) → c(z, f(b(y, z)), a)
b(z, b(c(a, y, a), f(f(x)))) → c(c(y, a, z), z, x)

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy


Polynomial Interpretation

Improved Usable rules

b(z, b(c(a, y, a), f(f(x)))) → c(c(y, a, z), z, x)c(c(z, y, a), a, a) → b(z, y)

The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:

c#(c(z, y, a), a, a) → b#(z, y)b#(z, b(c(a, y, a), f(f(x)))) → c#(c(y, a, z), z, x)