TIMEOUT

The TRS could not be proven terminating. The proof attempt took 60019 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (46ms).
 | – Problem 2 was processed with processor PolynomialLinearRange4iUR (2012ms).
 |    | – Problem 3 was processed with processor PolynomialLinearRange4iUR (1763ms).
 |    |    | – Problem 4 was processed with processor PolynomialLinearRange8NegiUR (22398ms).
 |    |    |    | – Problem 5 remains open; application of the following processors failed [DependencyGraph (0ms), PolynomialLinearRange8NegiUR (11222ms), DependencyGraph (2ms), ReductionPairSAT (20607ms)].

The following open problems remain:



Open Dependency Pair Problem 5

Dependency Pairs

f#(b(b(x, f(y)), z)) → f#(b(b(f(a), y), y))

Rewrite Rules

f(c(c(a, y, a), b(x, z), a)) → b(y, f(c(f(a), z, z)))f(b(b(x, f(y)), z)) → c(z, x, f(b(b(f(a), y), y)))
c(b(a, a), b(y, z), x) → b(a, b(z, z))

Original Signature

Termination of terms over the following signature is verified: f, b, c, a


Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

f#(c(c(a, y, a), b(x, z), a)) → f#(c(f(a), z, z))f#(b(b(x, f(y)), z)) → f#(a)
f#(b(b(x, f(y)), z)) → f#(b(b(f(a), y), y))f#(b(b(x, f(y)), z)) → c#(z, x, f(b(b(f(a), y), y)))
f#(c(c(a, y, a), b(x, z), a)) → c#(f(a), z, z)f#(c(c(a, y, a), b(x, z), a)) → f#(a)

Rewrite Rules

f(c(c(a, y, a), b(x, z), a)) → b(y, f(c(f(a), z, z)))f(b(b(x, f(y)), z)) → c(z, x, f(b(b(f(a), y), y)))
c(b(a, a), b(y, z), x) → b(a, b(z, z))

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy


The following SCCs where found

f#(c(c(a, y, a), b(x, z), a)) → f#(c(f(a), z, z))f#(b(b(x, f(y)), z)) → f#(a)
f#(b(b(x, f(y)), z)) → f#(b(b(f(a), y), y))f#(c(c(a, y, a), b(x, z), a)) → f#(a)

Problem 2: PolynomialLinearRange4iUR



Dependency Pair Problem

Dependency Pairs

f#(c(c(a, y, a), b(x, z), a)) → f#(c(f(a), z, z))f#(b(b(x, f(y)), z)) → f#(a)
f#(b(b(x, f(y)), z)) → f#(b(b(f(a), y), y))f#(c(c(a, y, a), b(x, z), a)) → f#(a)

Rewrite Rules

f(c(c(a, y, a), b(x, z), a)) → b(y, f(c(f(a), z, z)))f(b(b(x, f(y)), z)) → c(z, x, f(b(b(f(a), y), y)))
c(b(a, a), b(y, z), x) → b(a, b(z, z))

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy


Polynomial Interpretation

Improved Usable rules

c(b(a, a), b(y, z), x) → b(a, b(z, z))

The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:

f#(c(c(a, y, a), b(x, z), a)) → f#(a)

Problem 3: PolynomialLinearRange4iUR



Dependency Pair Problem

Dependency Pairs

f#(c(c(a, y, a), b(x, z), a)) → f#(c(f(a), z, z))f#(b(b(x, f(y)), z)) → f#(a)
f#(b(b(x, f(y)), z)) → f#(b(b(f(a), y), y))

Rewrite Rules

f(c(c(a, y, a), b(x, z), a)) → b(y, f(c(f(a), z, z)))f(b(b(x, f(y)), z)) → c(z, x, f(b(b(f(a), y), y)))
c(b(a, a), b(y, z), x) → b(a, b(z, z))

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy


Polynomial Interpretation

Improved Usable rules

c(b(a, a), b(y, z), x) → b(a, b(z, z))

The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:

f#(b(b(x, f(y)), z)) → f#(a)

Problem 4: PolynomialLinearRange8NegiUR



Dependency Pair Problem

Dependency Pairs

f#(c(c(a, y, a), b(x, z), a)) → f#(c(f(a), z, z))f#(b(b(x, f(y)), z)) → f#(b(b(f(a), y), y))

Rewrite Rules

f(c(c(a, y, a), b(x, z), a)) → b(y, f(c(f(a), z, z)))f(b(b(x, f(y)), z)) → c(z, x, f(b(b(f(a), y), y)))
c(b(a, a), b(y, z), x) → b(a, b(z, z))

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy


Polynomial Interpretation

Improved Usable rules

c(b(a, a), b(y, z), x) → b(a, b(z, z))f(b(b(x, f(y)), z)) → c(z, x, f(b(b(f(a), y), y)))
f(c(c(a, y, a), b(x, z), a)) → b(y, f(c(f(a), z, z)))

The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:

f#(c(c(a, y, a), b(x, z), a)) → f#(c(f(a), z, z))