TIMEOUT

The TRS could not be proven terminating. The proof attempt took 60000 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (2922ms).
 | – Problem 2 was processed with processor SubtermCriterion (2ms).
 | – Problem 3 was processed with processor SubtermCriterion (1ms).
 | – Problem 4 was processed with processor SubtermCriterion (1ms).
 | – Problem 5 was processed with processor SubtermCriterion (4ms).
 | – Problem 6 was processed with processor SubtermCriterion (1ms).
 | – Problem 7 was processed with processor SubtermCriterion (1ms).
 | – Problem 8 remains open; application of the following processors failed [SubtermCriterion (1ms), DependencyGraph (8ms), PolynomialLinearRange4iUR (3333ms), DependencyGraph (4ms), PolynomialLinearRange8NegiUR (10000ms), DependencyGraph (18ms), ReductionPairSAT (4030ms), DependencyGraph (44ms), ReductionPairSAT (3859ms), DependencyGraph (4ms), SizeChangePrinciple (timeout)].
 | – Problem 9 was processed with processor SubtermCriterion (1ms).
 |    | – Problem 12 was processed with processor ReductionPairSAT (69ms).
 | – Problem 10 was processed with processor SubtermCriterion (1ms).
 |    | – Problem 13 was processed with processor ReductionPairSAT (79ms).
 | – Problem 11 was processed with processor SubtermCriterion (3ms).

The following open problems remain:



Open Dependency Pair Problem 8

Dependency Pairs

top#(mark(X))top#(proper(X))top#(ok(X))top#(active(X))

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, top, cons, nil


Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

proper#(cons(X1, X2))proper#(X1)top#(ok(X))top#(active(X))
active#(2nd(X))2nd#(active(X))cons#(ok(X1), ok(X2))cons#(X1, X2)
from#(ok(X))from#(X)active#(cons(X1, X2))cons#(active(X1), X2)
2nd#(ok(X))2nd#(X)active#(take(X1, X2))take#(active(X1), X2)
active#(take(s(N), cons(X, XS)))cons#(X, take(N, XS))active#(sel(X1, X2))active#(X2)
active#(head(X))active#(X)top#(mark(X))proper#(X)
proper#(from(X))proper#(X)active#(2nd(X))active#(X)
top#(mark(X))top#(proper(X))proper#(cons(X1, X2))proper#(X2)
active#(take(X1, X2))active#(X2)proper#(2nd(X))2nd#(proper(X))
take#(X1, mark(X2))take#(X1, X2)sel#(X1, mark(X2))sel#(X1, X2)
active#(from(X))s#(X)head#(ok(X))head#(X)
proper#(s(X))proper#(X)proper#(head(X))head#(proper(X))
sel#(ok(X1), ok(X2))sel#(X1, X2)proper#(take(X1, X2))take#(proper(X1), proper(X2))
active#(cons(X1, X2))active#(X1)sel#(mark(X1), X2)sel#(X1, X2)
take#(mark(X1), X2)take#(X1, X2)proper#(head(X))proper#(X)
cons#(mark(X1), X2)cons#(X1, X2)2nd#(mark(X))2nd#(X)
active#(from(X))from#(active(X))from#(mark(X))from#(X)
top#(ok(X))active#(X)proper#(sel(X1, X2))sel#(proper(X1), proper(X2))
proper#(2nd(X))proper#(X)active#(sel(X1, X2))active#(X1)
active#(sel(s(N), cons(X, XS)))sel#(N, XS)proper#(take(X1, X2))proper#(X1)
active#(from(X))cons#(X, from(s(X)))proper#(from(X))from#(proper(X))
proper#(sel(X1, X2))proper#(X2)active#(take(s(N), cons(X, XS)))take#(N, XS)
take#(ok(X1), ok(X2))take#(X1, X2)active#(2nd(cons(X, XS)))head#(XS)
active#(sel(X1, X2))sel#(X1, active(X2))active#(sel(X1, X2))sel#(active(X1), X2)
head#(mark(X))head#(X)active#(from(X))active#(X)
proper#(take(X1, X2))proper#(X2)active#(head(X))head#(active(X))
active#(take(X1, X2))active#(X1)active#(s(X))s#(active(X))
s#(ok(X))s#(X)s#(mark(X))s#(X)
proper#(sel(X1, X2))proper#(X1)proper#(cons(X1, X2))cons#(proper(X1), proper(X2))
active#(s(X))active#(X)active#(take(X1, X2))take#(X1, active(X2))
proper#(s(X))s#(proper(X))active#(from(X))from#(s(X))

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, nil, top, cons

Strategy


The following SCCs where found

cons#(mark(X1), X2) → cons#(X1, X2)cons#(ok(X1), ok(X2)) → cons#(X1, X2)

sel#(mark(X1), X2) → sel#(X1, X2)sel#(ok(X1), ok(X2)) → sel#(X1, X2)
sel#(X1, mark(X2)) → sel#(X1, X2)

head#(ok(X)) → head#(X)head#(mark(X)) → head#(X)

active#(sel(X1, X2)) → active#(X2)active#(sel(X1, X2)) → active#(X1)
active#(from(X)) → active#(X)active#(s(X)) → active#(X)
active#(take(X1, X2)) → active#(X2)active#(take(X1, X2)) → active#(X1)
active#(head(X)) → active#(X)active#(2nd(X)) → active#(X)
active#(cons(X1, X2)) → active#(X1)

proper#(sel(X1, X2)) → proper#(X1)proper#(s(X)) → proper#(X)
proper#(head(X)) → proper#(X)proper#(2nd(X)) → proper#(X)
proper#(cons(X1, X2)) → proper#(X1)proper#(cons(X1, X2)) → proper#(X2)
proper#(take(X1, X2)) → proper#(X1)proper#(take(X1, X2)) → proper#(X2)
proper#(sel(X1, X2)) → proper#(X2)proper#(from(X)) → proper#(X)

take#(mark(X1), X2) → take#(X1, X2)take#(X1, mark(X2)) → take#(X1, X2)
take#(ok(X1), ok(X2)) → take#(X1, X2)

from#(mark(X)) → from#(X)from#(ok(X)) → from#(X)

top#(mark(X)) → top#(proper(X))top#(ok(X)) → top#(active(X))

2nd#(ok(X)) → 2nd#(X)2nd#(mark(X)) → 2nd#(X)

s#(mark(X)) → s#(X)s#(ok(X)) → s#(X)

Problem 2: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

head#(ok(X))head#(X)head#(mark(X))head#(X)

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, nil, top, cons

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

head#(ok(X))head#(X)head#(mark(X))head#(X)

Problem 3: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

cons#(mark(X1), X2)cons#(X1, X2)cons#(ok(X1), ok(X2))cons#(X1, X2)

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, nil, top, cons

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

cons#(mark(X1), X2)cons#(X1, X2)cons#(ok(X1), ok(X2))cons#(X1, X2)

Problem 4: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

s#(mark(X))s#(X)s#(ok(X))s#(X)

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, nil, top, cons

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

s#(mark(X))s#(X)s#(ok(X))s#(X)

Problem 5: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

proper#(sel(X1, X2))proper#(X1)proper#(s(X))proper#(X)
proper#(head(X))proper#(X)proper#(2nd(X))proper#(X)
proper#(cons(X1, X2))proper#(X1)proper#(cons(X1, X2))proper#(X2)
proper#(take(X1, X2))proper#(X1)proper#(take(X1, X2))proper#(X2)
proper#(sel(X1, X2))proper#(X2)proper#(from(X))proper#(X)

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, nil, top, cons

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

proper#(sel(X1, X2))proper#(X1)proper#(s(X))proper#(X)
proper#(cons(X1, X2))proper#(X1)proper#(head(X))proper#(X)
proper#(2nd(X))proper#(X)proper#(cons(X1, X2))proper#(X2)
proper#(take(X1, X2))proper#(X1)proper#(take(X1, X2))proper#(X2)
proper#(sel(X1, X2))proper#(X2)proper#(from(X))proper#(X)

Problem 6: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

from#(mark(X))from#(X)from#(ok(X))from#(X)

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, nil, top, cons

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

from#(mark(X))from#(X)from#(ok(X))from#(X)

Problem 7: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

active#(sel(X1, X2))active#(X2)active#(sel(X1, X2))active#(X1)
active#(from(X))active#(X)active#(s(X))active#(X)
active#(take(X1, X2))active#(X2)active#(take(X1, X2))active#(X1)
active#(head(X))active#(X)active#(2nd(X))active#(X)
active#(cons(X1, X2))active#(X1)

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, nil, top, cons

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

active#(sel(X1, X2))active#(X2)active#(from(X))active#(X)
active#(sel(X1, X2))active#(X1)active#(s(X))active#(X)
active#(take(X1, X2))active#(X2)active#(take(X1, X2))active#(X1)
active#(head(X))active#(X)active#(2nd(X))active#(X)
active#(cons(X1, X2))active#(X1)

Problem 9: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

sel#(mark(X1), X2)sel#(X1, X2)sel#(ok(X1), ok(X2))sel#(X1, X2)
sel#(X1, mark(X2))sel#(X1, X2)

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, nil, top, cons

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

sel#(mark(X1), X2)sel#(X1, X2)sel#(ok(X1), ok(X2))sel#(X1, X2)

Problem 12: ReductionPairSAT



Dependency Pair Problem

Dependency Pairs

sel#(X1, mark(X2))sel#(X1, X2)

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, cons, nil, top

Strategy


Function Precedence

mark < 2nd = sel# = from = 0 = s = take = active = ok = proper = head = sel = top = cons = nil

Argument Filtering

2nd: collapses to 1
mark: 1
sel#: collapses to 2
from: collapses to 1
0: all arguments are removed from 0
s: collapses to 1
take: collapses to 2
active: collapses to 1
ok: collapses to 1
proper: collapses to 1
head: 1
sel: 1 2
top: all arguments are removed from top
cons: all arguments are removed from cons
nil: all arguments are removed from nil

Status

mark: lexicographic with permutation 1 → 1
0: multiset
head: lexicographic with permutation 1 → 1
sel: lexicographic with permutation 1 → 1 2 → 2
top: multiset
cons: multiset
nil: multiset

Usable Rules

There are no usable rules.

The dependency pairs and usable rules are stronlgy conservative!

Eliminated dependency pairs

The following dependency pairs (at least) can be eliminated according to the given precedence.

sel#(X1, mark(X2)) → sel#(X1, X2)

Problem 10: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

take#(mark(X1), X2)take#(X1, X2)take#(X1, mark(X2))take#(X1, X2)
take#(ok(X1), ok(X2))take#(X1, X2)

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, nil, top, cons

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

take#(mark(X1), X2)take#(X1, X2)take#(ok(X1), ok(X2))take#(X1, X2)

Problem 13: ReductionPairSAT



Dependency Pair Problem

Dependency Pairs

take#(X1, mark(X2))take#(X1, X2)

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, cons, nil, top

Strategy


Function Precedence

2nd = mark = from = take# = 0 = s = take = active = ok = proper = head = sel = top = cons = nil

Argument Filtering

2nd: all arguments are removed from 2nd
mark: 1
from: all arguments are removed from from
take#: 2
0: all arguments are removed from 0
s: all arguments are removed from s
take: 1
active: all arguments are removed from active
ok: all arguments are removed from ok
proper: all arguments are removed from proper
head: 1
sel: all arguments are removed from sel
top: all arguments are removed from top
cons: all arguments are removed from cons
nil: all arguments are removed from nil

Status

2nd: multiset
mark: multiset
from: multiset
take#: lexicographic with permutation 2 → 1
0: multiset
s: multiset
take: lexicographic with permutation 1 → 1
active: multiset
ok: multiset
proper: multiset
head: lexicographic with permutation 1 → 1
sel: multiset
top: multiset
cons: multiset
nil: multiset

Usable Rules

There are no usable rules.

The dependency pairs and usable rules are stronlgy conservative!

Eliminated dependency pairs

The following dependency pairs (at least) can be eliminated according to the given precedence.

take#(X1, mark(X2)) → take#(X1, X2)

Problem 11: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

2nd#(ok(X))2nd#(X)2nd#(mark(X))2nd#(X)

Rewrite Rules

active(from(X))mark(cons(X, from(s(X))))active(head(cons(X, XS)))mark(X)
active(2nd(cons(X, XS)))mark(head(XS))active(take(0, XS))mark(nil)
active(take(s(N), cons(X, XS)))mark(cons(X, take(N, XS)))active(sel(0, cons(X, XS)))mark(X)
active(sel(s(N), cons(X, XS)))mark(sel(N, XS))active(from(X))from(active(X))
active(cons(X1, X2))cons(active(X1), X2)active(s(X))s(active(X))
active(head(X))head(active(X))active(2nd(X))2nd(active(X))
active(take(X1, X2))take(active(X1), X2)active(take(X1, X2))take(X1, active(X2))
active(sel(X1, X2))sel(active(X1), X2)active(sel(X1, X2))sel(X1, active(X2))
from(mark(X))mark(from(X))cons(mark(X1), X2)mark(cons(X1, X2))
s(mark(X))mark(s(X))head(mark(X))mark(head(X))
2nd(mark(X))mark(2nd(X))take(mark(X1), X2)mark(take(X1, X2))
take(X1, mark(X2))mark(take(X1, X2))sel(mark(X1), X2)mark(sel(X1, X2))
sel(X1, mark(X2))mark(sel(X1, X2))proper(from(X))from(proper(X))
proper(cons(X1, X2))cons(proper(X1), proper(X2))proper(s(X))s(proper(X))
proper(head(X))head(proper(X))proper(2nd(X))2nd(proper(X))
proper(take(X1, X2))take(proper(X1), proper(X2))proper(0)ok(0)
proper(nil)ok(nil)proper(sel(X1, X2))sel(proper(X1), proper(X2))
from(ok(X))ok(from(X))cons(ok(X1), ok(X2))ok(cons(X1, X2))
s(ok(X))ok(s(X))head(ok(X))ok(head(X))
2nd(ok(X))ok(2nd(X))take(ok(X1), ok(X2))ok(take(X1, X2))
sel(ok(X1), ok(X2))ok(sel(X1, X2))top(mark(X))top(proper(X))
top(ok(X))top(active(X))

Original Signature

Termination of terms over the following signature is verified: 2nd, mark, from, 0, s, take, active, ok, proper, head, sel, nil, top, cons

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

2nd#(ok(X))2nd#(X)2nd#(mark(X))2nd#(X)