TIMEOUT

The TRS could not be proven terminating. The proof attempt took 60002 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (281ms).
 | – Problem 2 was processed with processor SubtermCriterion (1ms).
 | – Problem 3 remains open; application of the following processors failed [SubtermCriterion (1ms), DependencyGraph (29ms), PolynomialLinearRange4iUR (1336ms), DependencyGraph (29ms), PolynomialLinearRange8NegiUR (13699ms), DependencyGraph (21ms), ReductionPairSAT (timeout)].
 | – Problem 4 was processed with processor SubtermCriterion (1ms).

The following open problems remain:



Open Dependency Pair Problem 3

Dependency Pairs

reach#(x, y, i, h) → if1#(eq(x, y), isEmpty(i), eq(x, from(i)), eq(y, to(i)), x, y, i, h)if4#(false, x, y, i, h) → reach#(to(i), y, union(rest(i), h), empty)
if4#(false, x, y, i, h) → reach#(x, y, rest(i), h)if3#(true, b3, x, y, i, h) → if4#(b3, x, y, i, h)
if1#(false, b1, b2, b3, x, y, i, h) → if2#(b1, b2, b3, x, y, i, h)if2#(false, b2, b3, x, y, i, h) → if3#(b2, b3, x, y, i, h)
if3#(false, b3, x, y, i, h) → reach#(x, y, rest(i), edge(from(i), to(i), h))

Rewrite Rules

eq(0, 0) → trueeq(0, s(x)) → false
eq(s(x), 0) → falseeq(s(x), s(y)) → eq(x, y)
or(true, y) → trueor(false, y) → y
union(empty, h) → hunion(edge(x, y, i), h) → edge(x, y, union(i, h))
isEmpty(empty) → trueisEmpty(edge(x, y, i)) → false
from(edge(x, y, i)) → xto(edge(x, y, i)) → y
rest(edge(x, y, i)) → irest(empty) → empty
reach(x, y, i, h) → if1(eq(x, y), isEmpty(i), eq(x, from(i)), eq(y, to(i)), x, y, i, h)if1(true, b1, b2, b3, x, y, i, h) → true
if1(false, b1, b2, b3, x, y, i, h) → if2(b1, b2, b3, x, y, i, h)if2(true, b2, b3, x, y, i, h) → false
if2(false, b2, b3, x, y, i, h) → if3(b2, b3, x, y, i, h)if3(false, b3, x, y, i, h) → reach(x, y, rest(i), edge(from(i), to(i), h))
if3(true, b3, x, y, i, h) → if4(b3, x, y, i, h)if4(true, x, y, i, h) → true
if4(false, x, y, i, h) → or(reach(x, y, rest(i), h), reach(to(i), y, union(rest(i), h), empty))

Original Signature

Termination of terms over the following signature is verified: to, edge, or, if3, if4, true, if1, if2, from, reach, isEmpty, 0, s, union, empty, false, rest, eq


Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

reach#(x, y, i, h) → if1#(eq(x, y), isEmpty(i), eq(x, from(i)), eq(y, to(i)), x, y, i, h)if3#(false, b3, x, y, i, h) → from#(i)
if3#(true, b3, x, y, i, h) → if4#(b3, x, y, i, h)if1#(false, b1, b2, b3, x, y, i, h) → if2#(b1, b2, b3, x, y, i, h)
reach#(x, y, i, h) → eq#(x, from(i))if2#(false, b2, b3, x, y, i, h) → if3#(b2, b3, x, y, i, h)
reach#(x, y, i, h) → isEmpty#(i)if3#(false, b3, x, y, i, h) → reach#(x, y, rest(i), edge(from(i), to(i), h))
if4#(false, x, y, i, h) → or#(reach(x, y, rest(i), h), reach(to(i), y, union(rest(i), h), empty))reach#(x, y, i, h) → eq#(x, y)
if3#(false, b3, x, y, i, h) → rest#(i)if4#(false, x, y, i, h) → reach#(to(i), y, union(rest(i), h), empty)
reach#(x, y, i, h) → to#(i)reach#(x, y, i, h) → from#(i)
reach#(x, y, i, h) → eq#(y, to(i))if4#(false, x, y, i, h) → reach#(x, y, rest(i), h)
if4#(false, x, y, i, h) → rest#(i)eq#(s(x), s(y)) → eq#(x, y)
if4#(false, x, y, i, h) → union#(rest(i), h)union#(edge(x, y, i), h) → union#(i, h)
if3#(false, b3, x, y, i, h) → to#(i)if4#(false, x, y, i, h) → to#(i)

Rewrite Rules

eq(0, 0) → trueeq(0, s(x)) → false
eq(s(x), 0) → falseeq(s(x), s(y)) → eq(x, y)
or(true, y) → trueor(false, y) → y
union(empty, h) → hunion(edge(x, y, i), h) → edge(x, y, union(i, h))
isEmpty(empty) → trueisEmpty(edge(x, y, i)) → false
from(edge(x, y, i)) → xto(edge(x, y, i)) → y
rest(edge(x, y, i)) → irest(empty) → empty
reach(x, y, i, h) → if1(eq(x, y), isEmpty(i), eq(x, from(i)), eq(y, to(i)), x, y, i, h)if1(true, b1, b2, b3, x, y, i, h) → true
if1(false, b1, b2, b3, x, y, i, h) → if2(b1, b2, b3, x, y, i, h)if2(true, b2, b3, x, y, i, h) → false
if2(false, b2, b3, x, y, i, h) → if3(b2, b3, x, y, i, h)if3(false, b3, x, y, i, h) → reach(x, y, rest(i), edge(from(i), to(i), h))
if3(true, b3, x, y, i, h) → if4(b3, x, y, i, h)if4(true, x, y, i, h) → true
if4(false, x, y, i, h) → or(reach(x, y, rest(i), h), reach(to(i), y, union(rest(i), h), empty))

Original Signature

Termination of terms over the following signature is verified: to, edge, or, if3, if4, true, if1, if2, from, reach, isEmpty, 0, s, union, empty, false, rest, eq

Strategy


The following SCCs where found

if4#(false, x, y, i, h) → reach#(to(i), y, union(rest(i), h), empty)reach#(x, y, i, h) → if1#(eq(x, y), isEmpty(i), eq(x, from(i)), eq(y, to(i)), x, y, i, h)
if3#(true, b3, x, y, i, h) → if4#(b3, x, y, i, h)if4#(false, x, y, i, h) → reach#(x, y, rest(i), h)
if1#(false, b1, b2, b3, x, y, i, h) → if2#(b1, b2, b3, x, y, i, h)if2#(false, b2, b3, x, y, i, h) → if3#(b2, b3, x, y, i, h)
if3#(false, b3, x, y, i, h) → reach#(x, y, rest(i), edge(from(i), to(i), h))

eq#(s(x), s(y)) → eq#(x, y)

union#(edge(x, y, i), h) → union#(i, h)

Problem 2: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

union#(edge(x, y, i), h) → union#(i, h)

Rewrite Rules

eq(0, 0) → trueeq(0, s(x)) → false
eq(s(x), 0) → falseeq(s(x), s(y)) → eq(x, y)
or(true, y) → trueor(false, y) → y
union(empty, h) → hunion(edge(x, y, i), h) → edge(x, y, union(i, h))
isEmpty(empty) → trueisEmpty(edge(x, y, i)) → false
from(edge(x, y, i)) → xto(edge(x, y, i)) → y
rest(edge(x, y, i)) → irest(empty) → empty
reach(x, y, i, h) → if1(eq(x, y), isEmpty(i), eq(x, from(i)), eq(y, to(i)), x, y, i, h)if1(true, b1, b2, b3, x, y, i, h) → true
if1(false, b1, b2, b3, x, y, i, h) → if2(b1, b2, b3, x, y, i, h)if2(true, b2, b3, x, y, i, h) → false
if2(false, b2, b3, x, y, i, h) → if3(b2, b3, x, y, i, h)if3(false, b3, x, y, i, h) → reach(x, y, rest(i), edge(from(i), to(i), h))
if3(true, b3, x, y, i, h) → if4(b3, x, y, i, h)if4(true, x, y, i, h) → true
if4(false, x, y, i, h) → or(reach(x, y, rest(i), h), reach(to(i), y, union(rest(i), h), empty))

Original Signature

Termination of terms over the following signature is verified: to, edge, or, if3, if4, true, if1, if2, from, reach, isEmpty, 0, s, union, empty, false, rest, eq

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

union#(edge(x, y, i), h) → union#(i, h)

Problem 4: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

eq#(s(x), s(y)) → eq#(x, y)

Rewrite Rules

eq(0, 0) → trueeq(0, s(x)) → false
eq(s(x), 0) → falseeq(s(x), s(y)) → eq(x, y)
or(true, y) → trueor(false, y) → y
union(empty, h) → hunion(edge(x, y, i), h) → edge(x, y, union(i, h))
isEmpty(empty) → trueisEmpty(edge(x, y, i)) → false
from(edge(x, y, i)) → xto(edge(x, y, i)) → y
rest(edge(x, y, i)) → irest(empty) → empty
reach(x, y, i, h) → if1(eq(x, y), isEmpty(i), eq(x, from(i)), eq(y, to(i)), x, y, i, h)if1(true, b1, b2, b3, x, y, i, h) → true
if1(false, b1, b2, b3, x, y, i, h) → if2(b1, b2, b3, x, y, i, h)if2(true, b2, b3, x, y, i, h) → false
if2(false, b2, b3, x, y, i, h) → if3(b2, b3, x, y, i, h)if3(false, b3, x, y, i, h) → reach(x, y, rest(i), edge(from(i), to(i), h))
if3(true, b3, x, y, i, h) → if4(b3, x, y, i, h)if4(true, x, y, i, h) → true
if4(false, x, y, i, h) → or(reach(x, y, rest(i), h), reach(to(i), y, union(rest(i), h), empty))

Original Signature

Termination of terms over the following signature is verified: to, edge, or, if3, if4, true, if1, if2, from, reach, isEmpty, 0, s, union, empty, false, rest, eq

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

eq#(s(x), s(y)) → eq#(x, y)