TIMEOUT

The TRS could not be proven terminating. The proof attempt took 60001 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (148ms).
 | – Problem 2 remains open; application of the following processors failed [SubtermCriterion (1ms), DependencyGraph (16ms), PolynomialLinearRange4iUR (3545ms), DependencyGraph (14ms), PolynomialLinearRange8NegiUR (timeout), DependencyGraph (12ms), ReductionPairSAT (22942ms), DependencyGraph (14ms), SizeChangePrinciple (209ms), ForwardNarrowing (2ms), BackwardInstantiation (3ms), ForwardInstantiation (3ms), Propagation (2ms)].
 | – Problem 3 was processed with processor SubtermCriterion (1ms).

The following open problems remain:



Open Dependency Pair Problem 2

Dependency Pairs

cond3#(true, x, y) → cond3#(gr(x, 0), p(x), y)cond2#(false, x, y) → cond4#(gr(y, 0), x, y)
cond4#(false, x, y) → cond1#(and(gr(x, 0), gr(y, 0)), x, y)cond2#(true, x, y) → cond3#(gr(x, 0), x, y)
cond1#(true, x, y) → cond2#(gr(x, y), x, y)cond3#(false, x, y) → cond1#(and(gr(x, 0), gr(y, 0)), x, y)
cond4#(true, x, y) → cond4#(gr(y, 0), x, p(y))

Rewrite Rules

cond1(true, x, y) → cond2(gr(x, y), x, y)cond2(true, x, y) → cond3(gr(x, 0), x, y)
cond2(false, x, y) → cond4(gr(y, 0), x, y)cond3(true, x, y) → cond3(gr(x, 0), p(x), y)
cond3(false, x, y) → cond1(and(gr(x, 0), gr(y, 0)), x, y)cond4(true, x, y) → cond4(gr(y, 0), x, p(y))
cond4(false, x, y) → cond1(and(gr(x, 0), gr(y, 0)), x, y)gr(0, x) → false
gr(s(x), 0) → truegr(s(x), s(y)) → gr(x, y)
and(true, true) → trueand(false, x) → false
and(x, false) → falsep(0) → 0
p(s(x)) → x

Original Signature

Termination of terms over the following signature is verified: cond2, cond3, cond4, 0, s, p, false, true, gr, cond1, and


Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

cond1#(true, x, y) → gr#(x, y)cond2#(false, x, y) → cond4#(gr(y, 0), x, y)
cond4#(true, x, y) → gr#(y, 0)cond3#(true, x, y) → gr#(x, 0)
cond3#(true, x, y) → p#(x)cond4#(false, x, y) → gr#(x, 0)
cond3#(false, x, y) → gr#(y, 0)cond2#(true, x, y) → gr#(x, 0)
cond4#(false, x, y) → and#(gr(x, 0), gr(y, 0))cond3#(true, x, y) → cond3#(gr(x, 0), p(x), y)
cond4#(false, x, y) → cond1#(and(gr(x, 0), gr(y, 0)), x, y)cond3#(false, x, y) → gr#(x, 0)
cond2#(true, x, y) → cond3#(gr(x, 0), x, y)cond2#(false, x, y) → gr#(y, 0)
cond1#(true, x, y) → cond2#(gr(x, y), x, y)gr#(s(x), s(y)) → gr#(x, y)
cond3#(false, x, y) → cond1#(and(gr(x, 0), gr(y, 0)), x, y)cond4#(true, x, y) → cond4#(gr(y, 0), x, p(y))
cond4#(true, x, y) → p#(y)cond3#(false, x, y) → and#(gr(x, 0), gr(y, 0))
cond4#(false, x, y) → gr#(y, 0)

Rewrite Rules

cond1(true, x, y) → cond2(gr(x, y), x, y)cond2(true, x, y) → cond3(gr(x, 0), x, y)
cond2(false, x, y) → cond4(gr(y, 0), x, y)cond3(true, x, y) → cond3(gr(x, 0), p(x), y)
cond3(false, x, y) → cond1(and(gr(x, 0), gr(y, 0)), x, y)cond4(true, x, y) → cond4(gr(y, 0), x, p(y))
cond4(false, x, y) → cond1(and(gr(x, 0), gr(y, 0)), x, y)gr(0, x) → false
gr(s(x), 0) → truegr(s(x), s(y)) → gr(x, y)
and(true, true) → trueand(false, x) → false
and(x, false) → falsep(0) → 0
p(s(x)) → x

Original Signature

Termination of terms over the following signature is verified: cond2, cond3, cond4, 0, s, p, true, false, gr, cond1, and

Strategy


The following SCCs where found

cond3#(true, x, y) → cond3#(gr(x, 0), p(x), y)cond2#(false, x, y) → cond4#(gr(y, 0), x, y)
cond4#(false, x, y) → cond1#(and(gr(x, 0), gr(y, 0)), x, y)cond2#(true, x, y) → cond3#(gr(x, 0), x, y)
cond1#(true, x, y) → cond2#(gr(x, y), x, y)cond3#(false, x, y) → cond1#(and(gr(x, 0), gr(y, 0)), x, y)
cond4#(true, x, y) → cond4#(gr(y, 0), x, p(y))

gr#(s(x), s(y)) → gr#(x, y)

Problem 3: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

gr#(s(x), s(y)) → gr#(x, y)

Rewrite Rules

cond1(true, x, y) → cond2(gr(x, y), x, y)cond2(true, x, y) → cond3(gr(x, 0), x, y)
cond2(false, x, y) → cond4(gr(y, 0), x, y)cond3(true, x, y) → cond3(gr(x, 0), p(x), y)
cond3(false, x, y) → cond1(and(gr(x, 0), gr(y, 0)), x, y)cond4(true, x, y) → cond4(gr(y, 0), x, p(y))
cond4(false, x, y) → cond1(and(gr(x, 0), gr(y, 0)), x, y)gr(0, x) → false
gr(s(x), 0) → truegr(s(x), s(y)) → gr(x, y)
and(true, true) → trueand(false, x) → false
and(x, false) → falsep(0) → 0
p(s(x)) → x

Original Signature

Termination of terms over the following signature is verified: cond2, cond3, cond4, 0, s, p, true, false, gr, cond1, and

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

gr#(s(x), s(y)) → gr#(x, y)