YES

The TRS could be proven terminating. The proof took 751 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (79ms).
 | – Problem 2 was processed with processor SubtermCriterion (1ms).
 | – Problem 3 was processed with processor SubtermCriterion (1ms).
 | – Problem 4 was processed with processor PolynomialLinearRange4iUR (121ms).
 | – Problem 5 was processed with processor SubtermCriterion (1ms).
 | – Problem 6 was processed with processor SubtermCriterion (1ms).
 | – Problem 7 was processed with processor PolynomialLinearRange4iUR (184ms).
 | – Problem 8 was processed with processor PolynomialLinearRange4iUR (89ms).

Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

quot#(s(x), s(y)) → minus#(x, y)shuffle#(add(n, x)) → reverse#(x)
less_leaves#(cons(u, v), cons(w, z)) → less_leaves#(concat(u, v), concat(w, z))shuffle#(add(n, x)) → shuffle#(reverse(x))
quot#(s(x), s(y)) → quot#(minus(x, y), s(y))app#(add(n, x), y) → app#(x, y)
reverse#(add(n, x)) → app#(reverse(x), add(n, nil))minus#(s(x), s(y)) → minus#(x, y)
less_leaves#(cons(u, v), cons(w, z)) → concat#(u, v)less_leaves#(cons(u, v), cons(w, z)) → concat#(w, z)
reverse#(add(n, x)) → reverse#(x)concat#(cons(u, v), y) → concat#(v, y)

Rewrite Rules

minus(x, 0) → xminus(s(x), s(y)) → minus(x, y)
quot(0, s(y)) → 0quot(s(x), s(y)) → s(quot(minus(x, y), s(y)))
app(nil, y) → yapp(add(n, x), y) → add(n, app(x, y))
reverse(nil) → nilreverse(add(n, x)) → app(reverse(x), add(n, nil))
shuffle(nil) → nilshuffle(add(n, x)) → add(n, shuffle(reverse(x)))
concat(leaf, y) → yconcat(cons(u, v), y) → cons(u, concat(v, y))
less_leaves(x, leaf) → falseless_leaves(leaf, cons(w, z)) → true
less_leaves(cons(u, v), cons(w, z)) → less_leaves(concat(u, v), concat(w, z))

Original Signature

Termination of terms over the following signature is verified: app, reverse, minus, true, leaf, add, concat, 0, s, shuffle, false, less_leaves, quot, cons, nil

Strategy


The following SCCs where found

less_leaves#(cons(u, v), cons(w, z)) → less_leaves#(concat(u, v), concat(w, z))

shuffle#(add(n, x)) → shuffle#(reverse(x))

quot#(s(x), s(y)) → quot#(minus(x, y), s(y))

app#(add(n, x), y) → app#(x, y)

minus#(s(x), s(y)) → minus#(x, y)

reverse#(add(n, x)) → reverse#(x)

concat#(cons(u, v), y) → concat#(v, y)

Problem 2: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

minus#(s(x), s(y)) → minus#(x, y)

Rewrite Rules

minus(x, 0) → xminus(s(x), s(y)) → minus(x, y)
quot(0, s(y)) → 0quot(s(x), s(y)) → s(quot(minus(x, y), s(y)))
app(nil, y) → yapp(add(n, x), y) → add(n, app(x, y))
reverse(nil) → nilreverse(add(n, x)) → app(reverse(x), add(n, nil))
shuffle(nil) → nilshuffle(add(n, x)) → add(n, shuffle(reverse(x)))
concat(leaf, y) → yconcat(cons(u, v), y) → cons(u, concat(v, y))
less_leaves(x, leaf) → falseless_leaves(leaf, cons(w, z)) → true
less_leaves(cons(u, v), cons(w, z)) → less_leaves(concat(u, v), concat(w, z))

Original Signature

Termination of terms over the following signature is verified: app, reverse, minus, true, leaf, add, concat, 0, s, shuffle, false, less_leaves, quot, cons, nil

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

minus#(s(x), s(y)) → minus#(x, y)

Problem 3: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

concat#(cons(u, v), y) → concat#(v, y)

Rewrite Rules

minus(x, 0) → xminus(s(x), s(y)) → minus(x, y)
quot(0, s(y)) → 0quot(s(x), s(y)) → s(quot(minus(x, y), s(y)))
app(nil, y) → yapp(add(n, x), y) → add(n, app(x, y))
reverse(nil) → nilreverse(add(n, x)) → app(reverse(x), add(n, nil))
shuffle(nil) → nilshuffle(add(n, x)) → add(n, shuffle(reverse(x)))
concat(leaf, y) → yconcat(cons(u, v), y) → cons(u, concat(v, y))
less_leaves(x, leaf) → falseless_leaves(leaf, cons(w, z)) → true
less_leaves(cons(u, v), cons(w, z)) → less_leaves(concat(u, v), concat(w, z))

Original Signature

Termination of terms over the following signature is verified: app, reverse, minus, true, leaf, add, concat, 0, s, shuffle, false, less_leaves, quot, cons, nil

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

concat#(cons(u, v), y) → concat#(v, y)

Problem 4: PolynomialLinearRange4iUR



Dependency Pair Problem

Dependency Pairs

quot#(s(x), s(y)) → quot#(minus(x, y), s(y))

Rewrite Rules

minus(x, 0) → xminus(s(x), s(y)) → minus(x, y)
quot(0, s(y)) → 0quot(s(x), s(y)) → s(quot(minus(x, y), s(y)))
app(nil, y) → yapp(add(n, x), y) → add(n, app(x, y))
reverse(nil) → nilreverse(add(n, x)) → app(reverse(x), add(n, nil))
shuffle(nil) → nilshuffle(add(n, x)) → add(n, shuffle(reverse(x)))
concat(leaf, y) → yconcat(cons(u, v), y) → cons(u, concat(v, y))
less_leaves(x, leaf) → falseless_leaves(leaf, cons(w, z)) → true
less_leaves(cons(u, v), cons(w, z)) → less_leaves(concat(u, v), concat(w, z))

Original Signature

Termination of terms over the following signature is verified: app, reverse, minus, true, leaf, add, concat, 0, s, shuffle, false, less_leaves, quot, cons, nil

Strategy


Polynomial Interpretation

Improved Usable rules

minus(s(x), s(y)) → minus(x, y)minus(x, 0) → x

The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:

quot#(s(x), s(y)) → quot#(minus(x, y), s(y))

Problem 5: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

reverse#(add(n, x)) → reverse#(x)

Rewrite Rules

minus(x, 0) → xminus(s(x), s(y)) → minus(x, y)
quot(0, s(y)) → 0quot(s(x), s(y)) → s(quot(minus(x, y), s(y)))
app(nil, y) → yapp(add(n, x), y) → add(n, app(x, y))
reverse(nil) → nilreverse(add(n, x)) → app(reverse(x), add(n, nil))
shuffle(nil) → nilshuffle(add(n, x)) → add(n, shuffle(reverse(x)))
concat(leaf, y) → yconcat(cons(u, v), y) → cons(u, concat(v, y))
less_leaves(x, leaf) → falseless_leaves(leaf, cons(w, z)) → true
less_leaves(cons(u, v), cons(w, z)) → less_leaves(concat(u, v), concat(w, z))

Original Signature

Termination of terms over the following signature is verified: app, reverse, minus, true, leaf, add, concat, 0, s, shuffle, false, less_leaves, quot, cons, nil

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

reverse#(add(n, x)) → reverse#(x)

Problem 6: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

app#(add(n, x), y) → app#(x, y)

Rewrite Rules

minus(x, 0) → xminus(s(x), s(y)) → minus(x, y)
quot(0, s(y)) → 0quot(s(x), s(y)) → s(quot(minus(x, y), s(y)))
app(nil, y) → yapp(add(n, x), y) → add(n, app(x, y))
reverse(nil) → nilreverse(add(n, x)) → app(reverse(x), add(n, nil))
shuffle(nil) → nilshuffle(add(n, x)) → add(n, shuffle(reverse(x)))
concat(leaf, y) → yconcat(cons(u, v), y) → cons(u, concat(v, y))
less_leaves(x, leaf) → falseless_leaves(leaf, cons(w, z)) → true
less_leaves(cons(u, v), cons(w, z)) → less_leaves(concat(u, v), concat(w, z))

Original Signature

Termination of terms over the following signature is verified: app, reverse, minus, true, leaf, add, concat, 0, s, shuffle, false, less_leaves, quot, cons, nil

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

app#(add(n, x), y) → app#(x, y)

Problem 7: PolynomialLinearRange4iUR



Dependency Pair Problem

Dependency Pairs

shuffle#(add(n, x)) → shuffle#(reverse(x))

Rewrite Rules

minus(x, 0) → xminus(s(x), s(y)) → minus(x, y)
quot(0, s(y)) → 0quot(s(x), s(y)) → s(quot(minus(x, y), s(y)))
app(nil, y) → yapp(add(n, x), y) → add(n, app(x, y))
reverse(nil) → nilreverse(add(n, x)) → app(reverse(x), add(n, nil))
shuffle(nil) → nilshuffle(add(n, x)) → add(n, shuffle(reverse(x)))
concat(leaf, y) → yconcat(cons(u, v), y) → cons(u, concat(v, y))
less_leaves(x, leaf) → falseless_leaves(leaf, cons(w, z)) → true
less_leaves(cons(u, v), cons(w, z)) → less_leaves(concat(u, v), concat(w, z))

Original Signature

Termination of terms over the following signature is verified: app, reverse, minus, true, leaf, add, concat, 0, s, shuffle, false, less_leaves, quot, cons, nil

Strategy


Polynomial Interpretation

Improved Usable rules

reverse(add(n, x)) → app(reverse(x), add(n, nil))app(nil, y) → y
app(add(n, x), y) → add(n, app(x, y))reverse(nil) → nil

The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:

shuffle#(add(n, x)) → shuffle#(reverse(x))

Problem 8: PolynomialLinearRange4iUR



Dependency Pair Problem

Dependency Pairs

less_leaves#(cons(u, v), cons(w, z)) → less_leaves#(concat(u, v), concat(w, z))

Rewrite Rules

minus(x, 0) → xminus(s(x), s(y)) → minus(x, y)
quot(0, s(y)) → 0quot(s(x), s(y)) → s(quot(minus(x, y), s(y)))
app(nil, y) → yapp(add(n, x), y) → add(n, app(x, y))
reverse(nil) → nilreverse(add(n, x)) → app(reverse(x), add(n, nil))
shuffle(nil) → nilshuffle(add(n, x)) → add(n, shuffle(reverse(x)))
concat(leaf, y) → yconcat(cons(u, v), y) → cons(u, concat(v, y))
less_leaves(x, leaf) → falseless_leaves(leaf, cons(w, z)) → true
less_leaves(cons(u, v), cons(w, z)) → less_leaves(concat(u, v), concat(w, z))

Original Signature

Termination of terms over the following signature is verified: app, reverse, minus, true, leaf, add, concat, 0, s, shuffle, false, less_leaves, quot, cons, nil

Strategy


Polynomial Interpretation

Improved Usable rules

concat(leaf, y) → yconcat(cons(u, v), y) → cons(u, concat(v, y))

The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:

less_leaves#(cons(u, v), cons(w, z)) → less_leaves#(concat(u, v), concat(w, z))