YES

The TRS could be proven terminating. The proof took 19 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (2ms).
 | – Problem 2 was processed with processor SubtermCriterion (1ms).

Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

f#(g(x))f#(x)f#(g(x))f#(a(g(g(f(x))), g(f(x))))

Rewrite Rules

f(g(x))f(a(g(g(f(x))), g(f(x))))

Original Signature

Termination of terms over the following signature is verified: f, g, a

Strategy


The following SCCs where found

f#(g(x)) → f#(x)

Problem 2: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

f#(g(x))f#(x)

Rewrite Rules

f(g(x))f(a(g(g(f(x))), g(f(x))))

Original Signature

Termination of terms over the following signature is verified: f, g, a

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

f#(g(x))f#(x)