YES
The TRS could be proven terminating. The proof took 19 ms.
Problem 1 was processed with processor DependencyGraph (2ms). | Problem 2 was processed with processor SubtermCriterion (1ms).
| f#(g(x)) | → | f#(x) | f#(g(x)) | → | f#(a(g(g(f(x))), g(f(x)))) |
| f(g(x)) | → | f(a(g(g(f(x))), g(f(x)))) |
Termination of terms over the following signature is verified: f, g, a
| f#(g(x)) → f#(x) |
| f#(g(x)) | → | f#(x) |
| f(g(x)) | → | f(a(g(g(f(x))), g(f(x)))) |
Termination of terms over the following signature is verified: f, g, a
The following projection was used:
Thus, the following dependency pairs are removed:
| f#(g(x)) | → | f#(x) |