YES

The TRS could be proven terminating. The proof took 307 ms.

The following DP Processors were used


Problem 1 was processed with processor BackwardsNarrowing (2ms).
 | – Problem 2 was processed with processor BackwardsNarrowing (1ms).

Problem 1: BackwardsNarrowing



Dependency Pair Problem

Dependency Pairs

f#(a, b, X)f#(X, X, X)

Rewrite Rules

f(a, b, X)f(X, X, X)ca
cb

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy

Context-sensitive strategy:
μ(T) = μ(b) = μ(c) = μ(a) = μ(c#) = ∅
μ(f) = μ(f#) = {1, 3}


The left-hand side of the rule f#(a, b, X) → f#(X, X, X) is backward narrowed to the following relevant and irrelevant terms (a narrowing is irrelevant if by dropping it the correctness (and completeness) of the processor is not influenced).
Relevant TermsIrrelevant Terms
f#(c, b, X) 
Thus, the rule f#(a, b, X) → f#(X, X, X) is replaced by the following rules:
f#(c, b, X) → f#(X, X, X)

Problem 2: BackwardsNarrowing



Dependency Pair Problem

Dependency Pairs

f#(c, b, X)f#(X, X, X)

Rewrite Rules

f(a, b, X)f(X, X, X)ca
cb

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy

Context-sensitive strategy:
μ(T) = μ(b) = μ(c) = μ(a) = μ(c#) = ∅
μ(f) = μ(f#) = {1, 3}


The left-hand side of the rule f#(c, b, X) → f#(X, X, X) is backward narrowed to the following relevant and irrelevant terms (a narrowing is irrelevant if by dropping it the correctness (and completeness) of the processor is not influenced).
Relevant TermsIrrelevant Terms
Thus, the rule f#(c, b, X) → f#(X, X, X) is deleted.