YES

The TRS could be proven terminating. The proof took 87 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (3ms).
 | – Problem 2 was processed with processor PolynomialLinearRange4 (55ms).

Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

c#f#(g(c))T(c)c#
T(g(x_1))T(x_1)

Rewrite Rules

cf(g(c))f(g(X))g(X)

Original Signature

Termination of terms over the following signature is verified: f, g, c

Strategy

Context-sensitive strategy:
μ(f) = μ(T) = μ(g) = μ(f#) = μ(c) = μ(c#) = ∅


The following SCCs where found

T(g(x_1)) → T(x_1)

Problem 2: PolynomialLinearRange4



Dependency Pair Problem

Dependency Pairs

T(g(x_1))T(x_1)

Rewrite Rules

cf(g(c))f(g(X))g(X)

Original Signature

Termination of terms over the following signature is verified: f, g, c

Strategy

Context-sensitive strategy:
μ(f) = μ(g) = μ(T) = μ(f#) = μ(c) = μ(c#) = ∅


Polynomial Interpretation

There are no usable rules

The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:

T(g(x_1))T(x_1)